5(1/4)-2(1/8)-(1/6)

5(1/4)-2(1/8)-(1/6)

First of all I'm going to assume that you mean 5 times (1/4) minus 2 times (1/8) minus (1/6), with no mixed numbers.

5* (1/4) - 2(1/8) - (1/6)

One of the ways to go about solving this problem would be to directly multiply out the terms first, instead of making the denominators of the fractions the same.

So:

$${\mathtt{5}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right) = {\frac{{\mathtt{5}}}{{\mathtt{4}}}}$$

$${\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{8}}}}\right) = {\frac{{\mathtt{1}}}{{\mathtt{4}}}}$$

And  $${\frac{{\mathtt{5}}}{{\mathtt{4}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}} = {\frac{{\mathtt{4}}}{{\mathtt{4}}}}$$ = 1

Now 1 is the same as 6/6

So:   $${\frac{{\mathtt{6}}}{{\mathtt{6}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{6}}}} = {\frac{{\mathtt{5}}}{{\mathtt{6}}}}$$

Nice explanation kitty.

I gave you a thumbs up. :)

Thanks, NinjaDevo:)