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5 1/4=×+7/16 How do I find x

 Feb 3, 2015

Best Answer 

 #2
avatar+118609 
+5

Just subtract 7/16  from both sides.

 

$$\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right){\mathtt{\,-\,}}\left({\frac{{\mathtt{7}}}{{\mathtt{16}}}}\right) = {\frac{{\mathtt{77}}}{{\mathtt{16}}}} = {\mathtt{4.812\: \!5}}$$

 Feb 3, 2015
 #1
avatar
+5

This is a tricky one. To start, lets fix those fractions. 

 

The mixed number 5 1/4 can be turned into an improper fraction. Since 5 is a whole number and it's taken by 1/4, each whole number means 4 added to the numerator. 

 

5 1/4

4 5/4

3 9/4

2 13/4

1 17/4 

21/4 

 

Now we have to deal with the 7/16. This is a simplified fraction. You can't exactly do anything with it. 

 

To solve this problem, we need to get x by itself. To do this, we need to subtract the 7/16 from 21/4. but we can't do this. 16 and 4 do not equal each other. To make this work, we have to change the 4 into 16. 4*4 is 16, so we multiply the TOP AND BOTTOM numbers of 21/4

 

4*21/4*4

 

Simplify.

 

84/16. 

 

Now, the denominators are the same. 

 

To get by itself, we need to use the inverse operation of + 7/16. We have to subtract 7/16 from BOTH sides of the equation. 

 

84/16 (-7/16) = x + 7/16 (-7/16)

 

The 7/16's cancel, so simplify. 

 

77/16 = x 

 

77/16 cannot be reduced. This is the final answer. 

 

Hope this helps. 

 Feb 3, 2015
 #2
avatar+118609 
+5
Best Answer

Just subtract 7/16  from both sides.

 

$$\left({\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right){\mathtt{\,-\,}}\left({\frac{{\mathtt{7}}}{{\mathtt{16}}}}\right) = {\frac{{\mathtt{77}}}{{\mathtt{16}}}} = {\mathtt{4.812\: \!5}}$$

Melody Feb 3, 2015

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