web2.0calc
 
+0  
 

 (5 × 10-12)(5 × 1016)

0
493
1
avatar

(5 × 10-12)(5 × 1016)

 Dec 1, 2014

Best Answer 

 #1
avatar+7188 
+5

$$\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{12}}\right){\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{1\,016}}\right) = {\mathtt{193\,040}}$$

.
 Dec 1, 2014

1+0 Answers

 #1
avatar+7188 
+5
Best Answer

$$\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{12}}\right){\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{1\,016}}\right) = {\mathtt{193\,040}}$$

happy7 Dec 1, 2014

0 Online Users

Top Users

avatar+15127 asinus moderator
avatar+2129 Bosco
avatar+762 history
avatar+113 thatgirlaj
avatar+108 ikleyn
avatar+63 TheDeathlyHallows
avatar+23 Dragononweb2.0calc
avatar+4 fof.urmum
avatar+0 D R Muse
avatar+0 The_Slipster
avatar+0 joshtheminer27

Sticky Topics