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5*2*(7+3)+7*0*(5-11)-23-(18*0)=

 Aug 4, 2014

Best Answer 

 #1
avatar+4473 
+8

5*2*(7+3)+7*0*(5-11)-23-(18*0)

Remember: pemdas [parentheses, exponents, multiplication, division, addition, & subtraction]

We must first evaluate the parentheses -->

5*2*(10)+7*0*(-6)-23-(0)

Next, we must perform multiplication -->

10*10+7*0-23 --> 100+7*0-23 --> 100 + 0 - 23 -->

Note that we had to do multiplication first so it is not 107*0-23.

Finally, we can just add and subtract to obtain our final answer -->

100 + 0 - 23 = 100 - 23 = 77.

 Aug 4, 2014
 #1
avatar+4473 
+8
Best Answer

5*2*(7+3)+7*0*(5-11)-23-(18*0)

Remember: pemdas [parentheses, exponents, multiplication, division, addition, & subtraction]

We must first evaluate the parentheses -->

5*2*(10)+7*0*(-6)-23-(0)

Next, we must perform multiplication -->

10*10+7*0-23 --> 100+7*0-23 --> 100 + 0 - 23 -->

Note that we had to do multiplication first so it is not 107*0-23.

Finally, we can just add and subtract to obtain our final answer -->

100 + 0 - 23 = 100 - 23 = 77.

AzizHusain Aug 4, 2014
 #2
avatar+8262 
+5

$$Answer: 77$$

Do you want to know how to solve it?

First, do the parentheses.

$$\left({\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\right) = {\mathtt{10}}$$

$$\left({\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{11}}\right) = -{\mathtt{6}}$$

$$\left({\mathtt{18}}{\mathtt{\,\times\,}}{\mathtt{0}}\right) = {\mathtt{0}}$$

Now, multiply.

$${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{10}} = {\mathtt{100}}$$

$${\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{0}}{\mathtt{\,\times\,}}-{\mathtt{6}} = {\mathtt{0}}{\mathtt{\,\times\,}}-{\mathtt{6}} = {\mathtt{0}}$$

Now add.

$${\mathtt{100}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0}} = {\mathtt{100}}$$

Now, subtract.

$${\mathtt{100}}{\mathtt{\,-\,}}{\mathtt{23}} = {\mathtt{77}}$$

So, $${\mathtt{77}}$$ is the answer.

Hope it helps!

 Aug 4, 2014

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