-5(3y+xlittle 2 in upper corner)(5-y)

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Guest Dec 4, 2014

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Best Answer

$$\\-5(3y^2)(5-y)\\\\
=-15y^2(5-y)\\\\
=-15y^2*5 \;\;-15y^2*-y\\\\
=-75y^2 \;\;+15y^3\\\\$$

Melody Dec 4, 2014

Melody · Answer 1 · 2014-12-04T12:51:12

$$\\-5(3y^2)(5-y)\\\\
=-15y^2(5-y)\\\\
=-15y^2*5 \;\;-15y^2*-y\\\\
=-75y^2 \;\;+15y^3\\\\$$

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