5(7f-3)=28(f-1)

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5(7f-3)=28(f-1)

Guest Jul 9, 2015

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Best Answer

+14538

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5(7f-3) =28(f-1)

35f -15 = 28f -28 | -28f and +15

7f = -13 => $${\mathtt{f}} = {\mathtt{\,-\,}}{\frac{{\mathtt{13}}}{{\mathtt{7}}}}$$

radix Jul 9, 2015

1⁺⁰ Answers

+14538

+5

Best Answer

5(7f-3) =28(f-1)

35f -15 = 28f -28 | -28f and +15

7f = -13 => $${\mathtt{f}} = {\mathtt{\,-\,}}{\frac{{\mathtt{13}}}{{\mathtt{7}}}}$$

radix Jul 9, 2015

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