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.5=(.85)^t

 Feb 11, 2015

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 #1
avatar+118667 
+5

 

$$\\.5=(.85)^t\\\\
log(0.5)=log(0.85)^t\\\\
log(0.5)=t*log(0.85)\\\\
t=\frac{log(0.5)}{log(0.85)}\\\\$$

 

$${\frac{{log}_{10}\left({\mathtt{0.5}}\right)}{{log}_{10}\left({\mathtt{0.85}}\right)}} = {\mathtt{4.265\: \!024\: \!281\: \!798\: \!725\: \!7}}$$

.
 Feb 11, 2015
 #1
avatar+118667 
+5
Best Answer

 

$$\\.5=(.85)^t\\\\
log(0.5)=log(0.85)^t\\\\
log(0.5)=t*log(0.85)\\\\
t=\frac{log(0.5)}{log(0.85)}\\\\$$

 

$${\frac{{log}_{10}\left({\mathtt{0.5}}\right)}{{log}_{10}\left({\mathtt{0.85}}\right)}} = {\mathtt{4.265\: \!024\: \!281\: \!798\: \!725\: \!7}}$$

Melody Feb 11, 2015

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