Line AB has the equation 3x - 4y + 5 = 0. Point (p, p+2) lies on line AB. What is the value of p?
+26400 Line AB has the equation 3x - 4y + 5 = 0. Point (p, p+2) lies on line AB. What is the value of p?
\(\small{ \begin{array}{rcl} 3x-4y+5 &=& 0\\ \\ \hline \\ x &=& p \\ y &=& p+2 \\ \\ \hline \\ 3(p)-4(p+2) + 5 &=& 0\\ 3p - 4p -8 +5 &=& 0\\ -p -3 &=& 0\\ p + 3 &=& 0\\ \mathbf{p} &\mathbf{=}& \mathbf{- 3} \end{array} }\)
The value of p is -3.
The Point (-3,-1) lies on line AB
