(51-[3+4]squared) to the power of 5
this was part of my math homework and i ahd a bit of difficulty doing it!!!!!!!
So you mean:
[ 51 - (3+4)^2 ]^5
Fist add the numbers in the round paranthesis (actually called addends). We know that the sum is 7, so we get:
( 51-7^2 )^5
Seven squared equals 49, we get:
(51-49)^5
51-49=2, we get:
2^5
2^5 = 2*2*2*2*2, we get:
32
So you mean:
[ 51 - (3+4)^2 ]^5
Fist add the numbers in the round paranthesis (actually called addends). We know that the sum is 7, so we get:
( 51-7^2 )^5
Seven squared equals 49, we get:
(51-49)^5
51-49=2, we get:
2^5
2^5 = 2*2*2*2*2, we get:
32
