Not quite Jay Cole
First I am goingto put brackets around 3c because I think that is what you really want -
I am mindreading I appologise if I get it wrong
(5c-8d/[3c]) - (2c-10d/[3c])
$$\\(5c-\frac{8d}{3c}) - (2c-\frac{10d}{3c})\\\\
=5c-\frac{8d}{3c} -1 (2c-\frac{10d}{3c})\\\\
=5c-\frac{8d}{3c} -2c+\frac{10d}{3c}\\\\
=5c-2c-\frac{8d}{3c} +\frac{10d}{3c}\\\\
=3c+\frac{-8d+10d}{3c}\\\\
=3c+\frac{2d}{3c}\\\\$$
ud get 3c-18d/3c. since the stuff on the buttom is the same u just have to deal with the stuff on top. i forget which ones the numberator and which ones the denomenator.
Not quite Jay Cole
First I am goingto put brackets around 3c because I think that is what you really want -
I am mindreading I appologise if I get it wrong
(5c-8d/[3c]) - (2c-10d/[3c])
$$\\(5c-\frac{8d}{3c}) - (2c-\frac{10d}{3c})\\\\
=5c-\frac{8d}{3c} -1 (2c-\frac{10d}{3c})\\\\
=5c-\frac{8d}{3c} -2c+\frac{10d}{3c}\\\\
=5c-2c-\frac{8d}{3c} +\frac{10d}{3c}\\\\
=3c+\frac{-8d+10d}{3c}\\\\
=3c+\frac{2d}{3c}\\\\$$