5sin^(2)x = 2sin(x)
How do you solve this? every time I try to solve it, I always get sin in the radical form. Please help!
Rewrite 5sin2(x) = 2sin(x) as: 5sin2(x) - 2sin(x) = 0.
Factoring: sin(x)[5sin(x) - 2] = 0
So, either: sin(x) = 0 or 5sin(x) - 2 = 0 ---> sin(x) = 0 or sin(x) = 2/5
Can you take it from here?
