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5sin(x) cos(x)=5sinx in the interval (0, 2pie)... How do you solve this equation?

 Apr 11, 2016
 #1
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Hello

 

5sin(x) cos(x)=5sinx in the interval (0, 2pie).

 

5sin(x) cos(x) = 5sin(x)

sin(x) cos(x) - sin(x) = 0

 

0°    0

30°  0.36

45°  -0.2

60°  -0.43

90°  -1

120° -1.299

150°

180°  0

210°

240°

270°

300°

330°

360° 0

 

5sin(x) cos(x)=5sinx is right at 0, pi, 2 pi.

 asinus :- )

laugh !

 Apr 11, 2016

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