3 friends divided some strawberries equally. After they each ate 4 strawberries, the total number of strawberries left was equal to the amount each friend had at the beginning. How many strawberries were there at first?

Guest Sep 2, 2021

#1**+1 **

How many strawberries were there at first?

**Hello Guest!**

\(\dfrac{x}{3}+\dfrac{x}{3}+\dfrac{x}{3}=x\\ 3\cdot (\dfrac{x}{3}-4)=\dfrac{x}{3}\\ x-12=\dfrac{x}{3}\\ \dfrac{2x}{3}=12\)

\(\large x=18\)

\({\color{blue}18\ strawberries}\ were\ there\ at\ first.\)

!

asinus Sep 3, 2021

#2**+1 **

Let total number of strawberries = x.

Since 3 friends divided strawberries equally therefore

each friends get x/3 strawberries.

Because x/3 + x/3 + x/3 = x.

Since, after they each ate 4 strawberries, the total number of strawberries left was equal to the amount each friend had at the beginning.

That is (x/3-4) + (x/3-4) (x/3-4) = x/3 (because at the beginning each friend has x/3 strawberries).

=> 3x/3 - 12 = x/3

=> n - 12 = x/3 => 3(n - 12) = x

=> 3n - 36 = n => 2n = 36 => n = 18

The total number of strawberries = 18

apsiganocj
Sep 9, 2021