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3 friends divided some strawberries equally. After they each ate 4 strawberries, the total number of strawberries left was equal to the amount each friend had at the beginning. How many strawberries were there at first?

 Sep 2, 2021
 #1
avatar+12194 
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 How many strawberries were there at first?

 

Hello Guest!

 

\(\dfrac{x}{3}+\dfrac{x}{3}+\dfrac{x}{3}=x\\ 3\cdot (\dfrac{x}{3}-4)=\dfrac{x}{3}\\ x-12=\dfrac{x}{3}\\ \dfrac{2x}{3}=12\)

 

\(\large x=18\)

\({\color{blue}18\ strawberries}\ were\ there\ at\ first.\)

laugh  !

 Sep 3, 2021
 #2
avatar+254 
+1

Let total number of strawberries = x.

Since 3 friends divided strawberries equally therefore

each friends get x/3 strawberries.

   Because           x/3 + x/3 + x/3 = x.

 

 

Since, after they each ate 4 strawberries, the total number of strawberries left was equal to the amount each friend had at the beginning.

That is (x/3-4) + (x/3-4) (x/3-4) = x/3 (because at the beginning each friend has x/3 strawberries).

 

 

=>  3x/3 - 12 = x/3

=>  n - 12 = x/3     =>  3(n - 12) = x

=>  3n - 36 = n   =>  2n = 36   =>  n = 18

The total number of strawberries = 18

apsiganocj  Sep 9, 2021

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