Solve the following system:
{13 y-5 x = -7 | (equation 1)
5 x+4 y = 24 | (equation 2)
Add equation 1 to equation 2:
{-(5 x)+13 y = -7 | (equation 1)
0 x+17 y = 17 | (equation 2)
Divide equation 2 by 17:
{-(5 x)+13 y = -7 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 13 × (equation 2) from equation 1:
{-(5 x)+0 y = -20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by -5:
{x+0 y = 4 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: |{x = 4 y=1
