That's the question I thought you might ask !!!
We're trying to "match" terms so that, when we subtract one equation from the other, a variable "disappears."
Note that we could have mutiplied x + y = 1 by 6 on both sides giving 6x + 6y = 6
And, if I subtracted this from 5x + 6y = 6 notice that the "y's" would have disappeared, thusly
5x + 6y = 6 ⇒ 5x + 6y = 6
-[6x + 6y = 6] ⇒ - 6x - 6y = -6
---------------- ----------------
-1x = 0 so ... x = 0
And we could have found "y" by substituting 0 in for "x" into the equation x + y = 1.....we would then find that y =1 ....just like before !!
This is an topic in Algebra (I don't know if you've encountered that or not)...so, if you haven't, don't worry about it too much....!!
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y=1 x=0
The way we get this is called solving by elimination. First take the equations with the nines and divide both sides by 9, this produces x+y=1. We then multiply this by five to get 5x+5y=5. Subtracting this from the fist equation gives us y=1. By substituting y=1 back into either equation we get our value for x. For example:
y+x=1
1+x=1
x=0
Nice explanation, jboy314.....3 points and a thumbs-up from me.....
BTW...welcome to the forum....I don't believe I've seen you here before.....
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jboy314 pls can u show its working becoz i think i may understand much nicely then !btw u explained it really very nicely but i am still unable to get it maybe becoz i have the habbit of seeing the working !lol! CPhill i saw jboy314 before answering really very good to some questions!so jboy314 if u dont mind pls can u show me the working !![]()
Here's what jboy314 did, rosala
He took this equation ..... 9x + 9y = 9 and divided every term by 9.....so we have
9x/9 + 9y/9 = 9/9 and this gives us
x + y = 1 then, he multiplied every term by 5 ..(the reason for this will be clear in a second).. so we have
5x + 5y = 1 Notice carefully, what happens if I take this equation and subtract it from 5x + 6y =6, we have:
5x + 6y = 6 ⇒ 5x + 6y = 6
- (5x + 5y = 5) ⇒ -5x - 5y = -5
----------------------- -----------------
y = 1
( Notice how the 5x terms cancelled each other !!!! That's why it's called the "elimination" method...jboy314 saw that he could eliminate "x" by multiplying x + y = 1 by 5 and then subtracting it from the other equation !!!! )
Now, all we need to do is to substitute 1 for y in any of the equations to find "x"...using x + y = 1 is easiest..so we have
x + (1) = 1 subtract 1 from both sides
- 1 = -1
---------------
x = 0
So x = 0 and y =1 are our solutions !!!
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CPhill ive undertood the method and how u got the answer but still i have one doubt left , its that how do we know that we have to multiply every term by 5 to get the answer??!!![]()
That's the question I thought you might ask !!!
We're trying to "match" terms so that, when we subtract one equation from the other, a variable "disappears."
Note that we could have mutiplied x + y = 1 by 6 on both sides giving 6x + 6y = 6
And, if I subtracted this from 5x + 6y = 6 notice that the "y's" would have disappeared, thusly
5x + 6y = 6 ⇒ 5x + 6y = 6
-[6x + 6y = 6] ⇒ - 6x - 6y = -6
---------------- ----------------
-1x = 0 so ... x = 0
And we could have found "y" by substituting 0 in for "x" into the equation x + y = 1.....we would then find that y =1 ....just like before !!
This is an topic in Algebra (I don't know if you've encountered that or not)...so, if you haven't, don't worry about it too much....!!
![]()
Thanks for jumping in and cleaning up what i left behind the curtain so to speak. Good thread!