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5y2+9y+4=0

Guest Mar 28, 2017
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5y2+9y+4=0

 

\(5y^2+9y+4=0\\ y = {-b \pm \sqrt{b^2-4ac} \over 2a}\\ y = {-9 \pm \sqrt{81-80} \over 10}\\ y = {-9 \pm 1 \over 10}\\ y=\frac{-8}{10}\qquad or \qquad \frac{-10}{10}\\ y=\frac{-4}{5}\qquad or \qquad y=-1\\ \)

Melody  Mar 28, 2017

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