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(-6)^3/(-3)^2+(-2)^3(5)-(-7)^2(2)/(3)^2

math
 Aug 18, 2014

Best Answer 

 #2
avatar+118723 
+5

$${\frac{{\left(-{\mathtt{6}}\right)}^{{\mathtt{3}}}}{{\left(-{\mathtt{3}}\right)}^{{\mathtt{2}}}}}{\mathtt{\,\small\textbf+\,}}{\left(-{\mathtt{2}}\right)}^{{\mathtt{3}}}{\mathtt{\,\times\,}}\left({\mathtt{5}}\right){\mathtt{\,-\,}}{\frac{{\left(-{\mathtt{7}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right)}{{\left({\mathtt{3}}\right)}^{{\mathtt{2}}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{674}}}{{\mathtt{9}}}} = -{\mathtt{74.888\: \!888\: \!888\: \!888\: \!888\: \!9}}$$

 

$$\\(-6)^3/(-3)^2+(-2)^3(5)-(-7)^2(2)/(3)^2\\\\
=-216/9+-8*(5)-49*(2)/9\\\\
=-216/9-40-98/9\\\\
=-24-40-10\frac{8}{9}\\\\
=-64-10\frac{8}{9}\\\\
=-74\frac{8}{9}$$

.
 Aug 20, 2014
 #1
avatar
0

-74.8888888888888889

 Aug 18, 2014
 #2
avatar+118723 
+5
Best Answer

$${\frac{{\left(-{\mathtt{6}}\right)}^{{\mathtt{3}}}}{{\left(-{\mathtt{3}}\right)}^{{\mathtt{2}}}}}{\mathtt{\,\small\textbf+\,}}{\left(-{\mathtt{2}}\right)}^{{\mathtt{3}}}{\mathtt{\,\times\,}}\left({\mathtt{5}}\right){\mathtt{\,-\,}}{\frac{{\left(-{\mathtt{7}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right)}{{\left({\mathtt{3}}\right)}^{{\mathtt{2}}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{674}}}{{\mathtt{9}}}} = -{\mathtt{74.888\: \!888\: \!888\: \!888\: \!888\: \!9}}$$

 

$$\\(-6)^3/(-3)^2+(-2)^3(5)-(-7)^2(2)/(3)^2\\\\
=-216/9+-8*(5)-49*(2)/9\\\\
=-216/9-40-98/9\\\\
=-24-40-10\frac{8}{9}\\\\
=-64-10\frac{8}{9}\\\\
=-74\frac{8}{9}$$

Melody Aug 20, 2014

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