when sqrt((-s)^2+(-8)^2)=10 why is s=6 and -6 and not 2
\(When \sqrt{(-s)^2+(-8)^2}=10\ why\ is\ s=6\ and -6\ and\ not\ 2? \)
Hello Guest!
\((-s)^2+(-8)^2=100\\ -s=\pm \sqrt{100-64}\\ -s=\pm6\)
\(s_1=6\\ s_2=-6\) therefore!
!