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6^(x-3)=2^x      x= ?

 Oct 27, 2014

Best Answer 

 #1
avatar+130511 
+5

6^(x-3)=2^x  take the log of both sides

log6^(x-3) = log 2^x      and by a log property we have

(x-3)log6= xlog2   simplify

xlog6 - 3log6 = xlog2      rearrange

xlog6 - xlog2 = 3log6      factor

x(log6 - log2) = 3log6      divide both sides by (log6 - log2)

x =  (3log6) /(log6 - log2)  = about 4.89

 

 Oct 27, 2014
 #1
avatar+130511 
+5
Best Answer

6^(x-3)=2^x  take the log of both sides

log6^(x-3) = log 2^x      and by a log property we have

(x-3)log6= xlog2   simplify

xlog6 - 3log6 = xlog2      rearrange

xlog6 - xlog2 = 3log6      factor

x(log6 - log2) = 3log6      divide both sides by (log6 - log2)

x =  (3log6) /(log6 - log2)  = about 4.89

 

CPhill Oct 27, 2014

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