6(x-3)=2x+38

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6(x-3)=2x+38

Guest Oct 2, 2014

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Best Answer

6(x-3)=2x+38 distribute the 6 over the terms in the parentheses on the left

6x - 18 = 2x + 38 add 18 to both sides and subtract 2x from both sides

4x = 56 divide both sides by 4

x = 14

CPhill Oct 2, 2014

CPhill · Answer 1 · 2014-10-02T10:09:19

6(x-3)=2x+38 distribute the 6 over the terms in the parentheses on the left

6x - 18 = 2x + 38 add 18 to both sides and subtract 2x from both sides

4x = 56 divide both sides by 4

x = 14