#1**+5 **

Hard to answer this without knowing what you mean. Instead of a comma, should there be another sign of operation?

Guest Mar 11, 2015

#2**+5 **

Assuming this is

$$6x^{1.7}+4=14$$

subtract 4 from both sides

$$6x^{1.7}=10$$

divide by 6

$$x^{1.7}=\frac{10}{6}$$

Take logs of both sides and use the fact that log(a^{b}) = b*log(a) and log(a/b) = log(a) - log(b)

$$1.7\log{x}=\log{10}-\log{6}$$

divide by 1.7

$$\log{x}=\frac{\log{10}-\log{6}}{1.7}$$

Use the fact that log_{10}a = b means a = 10^{b}

$$x=10^{\frac{\log{10}-\log{6}}{1.7}}$$

and since log_{10}10 = 1

$$x=10^{\frac{1-\log{6}}{1.7}}$$

You can complete the calculation.

.

Alan Mar 11, 2015