7^2+(-2)^3/(-2)^2

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7^2+(-2)^3/(-2)^2

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7^2+(-2)^3/(-2)^2

Guest Nov 17, 2014

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${{\mathtt{7}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\left(-{\mathtt{2}}\right)}^{{\mathtt{3}}}}{{\left(-{\mathtt{2}}\right)}^{{\mathtt{2}}}}} = {\mathtt{47}}$

Tiddle Nov 17, 2014

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Tiddle · Answer 1 · 2014-11-17T11:02:37

${{\mathtt{7}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\left(-{\mathtt{2}}\right)}^{{\mathtt{3}}}}{{\left(-{\mathtt{2}}\right)}^{{\mathtt{2}}}}} = {\mathtt{47}}$

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7^2+(-2)^3/(-2)^2

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7^2+(-2)^3/(-2)^2

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