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7(cos330+ i sin330)

 Dec 11, 2014

Best Answer 

 #2
avatar+118703 
+10

or

 

7(cos330+isin330)=7(cos(π/6)+isin(π/6))=7eπi/6

 Dec 11, 2014
 #1
avatar+130477 
+5

7(cos330+ i sin330) =

7( √3/2 - 1/2i) =

[ 7√3 - 7i ] / 2 =

(7/2)√3 - (7/2) i

 

 Dec 11, 2014
 #2
avatar+118703 
+10
Best Answer

or

 

7(cos330+isin330)=7(cos(π/6)+isin(π/6))=7eπi/6

Melody Dec 11, 2014

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