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7(cos330+ i sin330)

Guest Dec 11, 2014

Best Answer 

 #2
avatar+93691 
+10

or

 

$$7(cos330+ i sin330)\; = \;7(cos(-\pi/6)+isin(-\pi/6)) = 7e^{-\pi i/6}$$

Melody  Dec 11, 2014
 #1
avatar+90180 
+5

7(cos330+ i sin330) =

7( √3/2 - 1/2i) =

[ 7√3 - 7i ] / 2 =

(7/2)√3 - (7/2) i

 

CPhill  Dec 11, 2014
 #2
avatar+93691 
+10
Best Answer

or

 

$$7(cos330+ i sin330)\; = \;7(cos(-\pi/6)+isin(-\pi/6)) = 7e^{-\pi i/6}$$

Melody  Dec 11, 2014

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