7(cos330+ i sin330)

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7(cos330+ i sin330)

Guest Dec 11, 2014

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Best Answer

or

$$7(cos330+ i sin330)\; = \;7(cos(-\pi/6)+isin(-\pi/6)) = 7e^{-\pi i/6}$$

Melody Dec 11, 2014

Melody · Answer 1 · 2014-12-11T05:41:17

or

$$7(cos330+ i sin330)\; = \;7(cos(-\pi/6)+isin(-\pi/6)) = 7e^{-\pi i/6}$$

CPhill · Answer 2 · 2014-12-11T05:03:42

7(cos330+ i sin330) =

7( √3/2 - 1/2i) =

[ 7√3 - 7i ] / 2 =

(7/2)√3 - (7/2) i