Can anybody help me with this one math problem I have? I still need this question answered here. Thank You!

GAMEMASTERX40 Feb 3, 2020

#1**+1 **

An Identity:

\(sec^2(\theta)= 1+tan^2(\theta)\)

"Given \(tan(\theta)=3\)"

I think that's all we need?

then

\(tan^2(\theta)=3^2=9\)

\(sec^2(\theta)=1+9=10\)

\(sec(\theta)=\sqrt{10}=3.16227766..approx.=3.16\)

We didn't take the negative square root since:

\(cos(\theta)>0\) and \(sec(\theta)=\frac{1}{cos(\theta)}\)

Thus \(sec(\theta)\) must be positive.

Guest Feb 3, 2020