+73 Can anybody help me with this one math problem I have? I still need this question answered here. Thank You!
An Identity:
\(sec^2(\theta)= 1+tan^2(\theta)\)
"Given \(tan(\theta)=3\)"
I think that's all we need?
then
\(tan^2(\theta)=3^2=9\)
\(sec^2(\theta)=1+9=10\)
\(sec(\theta)=\sqrt{10}=3.16227766..approx.=3.16\)
We didn't take the negative square root since:
\(cos(\theta)>0\) and \(sec(\theta)=\frac{1}{cos(\theta)}\)
Thus \(sec(\theta)\) must be positive.
