+0  
 
0
633
1
avatar

(7 times ten to the 17 power) times (8 times 10 to the negative 28th power)

 Mar 26, 2015

Best Answer 

 #1
avatar+118608 
+5

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{17}}}\right){\mathtt{\,\times\,}}\left({\mathtt{8}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{28}}}\right)$$

 

= $${\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{17}}{\mathtt{\,-\,}}{\mathtt{28}}\right)}$$

 

= $${\mathtt{56}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{11}}\right)}$$

 

= $${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{1}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{11}}}$$

 

= $${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{11}}\right)}$$

 

$${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{10}}}$$

.
 Mar 26, 2015
 #1
avatar+118608 
+5
Best Answer

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{17}}}\right){\mathtt{\,\times\,}}\left({\mathtt{8}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{28}}}\right)$$

 

= $${\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{17}}{\mathtt{\,-\,}}{\mathtt{28}}\right)}$$

 

= $${\mathtt{56}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{11}}\right)}$$

 

= $${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{1}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{11}}}$$

 

= $${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{11}}\right)}$$

 

$${\mathtt{5.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{10}}}$$

Melody Mar 26, 2015

0 Online Users