8^1/6 x 2^x = 32^1/2 work out the value of x
\((2^{3})^{1\over6}\cdot2^x=32^{1\over2}\)
\(2^{1\over2}\cdot2^x=32^{1\over2}\)
\(2^{{1\over2}+x}=2^{6\cdot{1\over2}} = 2^3\)
\({1\over2}+x=3\)
\(x={5\over2}\)