8^1/6 x 2^x = 32^1/2 work out the value of x

\((2^{3})^{1\over6}\cdot2^x=32^{1\over2}\)

\(2^{1\over2}\cdot2^x=32^{1\over2}\)

\(2^{{1\over2}+x}=2^{6\cdot{1\over2}} = 2^3\)

\({1\over2}+x=3\)

\(x={5\over2}\)

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