8(-3/2+6)

8(-3/2x+6)=-9(4/3x-8) 

 

$$\begin{array}{rll}
8(\frac{-3x}{2}+6)&=&-9(\frac{4x}{3}-8) \\\\
\frac{-3*8x}{2}+6*8&=&\frac{-9*4x}{3}--9*8 \\\\
-12x+48&=&-12x+72 \\\\
48&=&72 \\\\
\end{array}\\\\
No Solution$$

$${\mathtt{8}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}\right) = {\mathtt{\,-\,}}\left({\mathtt{9}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{8}}\right)\right) \Rightarrow \left\{ \begin{array}{l}\end{array} \right\}$$

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