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8. In how many ways can 10 persons be seated in a round table if the host insists on occupying his favorite chair? (permutation)

 Sep 12, 2014

Best Answer 

 #1
avatar+33653 
+5

There are 9 possibilities for the person to the right of the host.  For each of those there are 8 possibilities for the person to their right.  For each of those ... etc.  This makes 9! arrangements in all.

$${\mathtt{9}}{!} = {\mathtt{362\,880}}$$ 

 Sep 12, 2014
 #1
avatar+33653 
+5
Best Answer

There are 9 possibilities for the person to the right of the host.  For each of those there are 8 possibilities for the person to their right.  For each of those ... etc.  This makes 9! arrangements in all.

$${\mathtt{9}}{!} = {\mathtt{362\,880}}$$ 

Alan Sep 12, 2014

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