8 men and 7 women find probability of 4 men and 2 women
The number of total sets possible by choosing any 6 people from 15 = C(15,6) = 5005
But the only ones we're intereseted in are the ones where we choose 4 men from 8 and 2 women from 7 = C(8,4) * C(7,2) = 1470
So.....1470/5005 = about 29.3%