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(8^n)^7=8^21
 May 13, 2016
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Solve for n over the real numbers:
8^(7 n) = 9223372036854775808

 

8^(7 n) = 2^(21 n):
2^(21 n) = 9223372036854775808

 

9223372036854775808 = 2^63:
2^(21 n) = 2^63

 

Equate exponents of 2 on both sides:
21 n = 63

 

All equations give n = 3 as the solution:
Answer: | n = 3

 May 13, 2016

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