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8/〖(x-y)〗^2 ÷ 12/(x^2-y^2 )

 Mar 10, 2015

Best Answer 

 #1
avatar+23247 
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8 / (x - y)²  ÷ 12 / (x² - y²)

=  8 / (x - y)²  ·  (x² - y²) / 12

=  [ 8 · (x² - y²) ] / [ (x - y)²  · 12 ]

=  [ 8 · (x + y)(x - y) ] / [ (x - y)(x - y) · 12 ]

Reduce 8/12 = 2/3 and cancel the factors (x - y) from the numerator and denominator:

=  [ 2 · (x + y) ] / [ 3 · (x - y) ]

 Mar 10, 2015
 #1
avatar+23247 
+5
Best Answer

8 / (x - y)²  ÷ 12 / (x² - y²)

=  8 / (x - y)²  ·  (x² - y²) / 12

=  [ 8 · (x² - y²) ] / [ (x - y)²  · 12 ]

=  [ 8 · (x + y)(x - y) ] / [ (x - y)(x - y) · 12 ]

Reduce 8/12 = 2/3 and cancel the factors (x - y) from the numerator and denominator:

=  [ 2 · (x + y) ] / [ 3 · (x - y) ]

geno3141 Mar 10, 2015

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