8 + y = 8 – y
What is the only value for y that makes this equation true?
\(y=0\) is the answer
Let's look at the original equation:
\(8+y=8-y\)
To solve this, we must isolate y. This means that we need to get the equation into y equals form.
\(8+y=8-y\) Subtract 8 on both sides
If you subtract a number on one side of the equation, you must do that on the other, of course. When you subtract 8 on both sides, you are left with:
\(y=-y\) Add y to both sides
\(y+y=0\) Combine like terms
\(2y=0\) Divide by 2 to isolate y
\(y=0\)
If you are ever unsure whether an answer is correct or not, plug the value you got back in the original equation:
\(8+0=8-0\)
\(8=8\)
This statement is true, so y=0 is the correct and the only correct value for y.