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8cos(x)sin(x)−2ctg(x)csc2(x)=0

how do you solve

 Jun 14, 2016
 #1
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8cos(x)sin(x)−2ctg(x)csc2(x)=0

 

8cosxsinx  - 2 [ cosx/ sinx] * [ 1/ sin2x]  = 0

 

8 sinxcosx] - 2 [cosx / sinx] * [ 1/ (2sinxcosx)]  = 0

 

8 sinxcosx - 1/  sin^2x  = 0

 

8sin^3xcosx - 1   =  0

 

Here's a graph of the solutions :  https://www.desmos.com/calculator/soaaiu3gmp

 

They occur at about   31.87°  + n* 180°    and at  about 82.64° + n * 180°    where n  is an integer

 

 

 

cool cool cool

 Jun 14, 2016

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