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(8d³+8d²+3d±1)-(d³+6d²)=?

 Nov 13, 2014

Best Answer 

 #1
avatar+118723 
+5

$$(8d^3+8d^2+3d\pm1)-1(d^3+6d^2)\\
=8d^3+8d^2+3d\pm1-d^3-6d^2\\
=8d^3-d^3+8d^2-6d^2+3d\pm1\\
=7d^3+2d^2+3d\pm1\\$$

.
 Nov 13, 2014
 #1
avatar+118723 
+5
Best Answer

$$(8d^3+8d^2+3d\pm1)-1(d^3+6d^2)\\
=8d^3+8d^2+3d\pm1-d^3-6d^2\\
=8d^3-d^3+8d^2-6d^2+3d\pm1\\
=7d^3+2d^2+3d\pm1\\$$

Melody Nov 13, 2014

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