9 ( 4 ( 2n + r ) - 11r ) + 3 ( r - n )
Work from the innermost parentheses first: Solve 4 ( 2n + r ) by using the distributive property:
4 ( 2n + r ) = 4 x 2n + 4 x r = 8n + 4r
This gives us: 9 ( 8n + 4r - 11r ) + 3 ( r - n )
Still working inside the first set of parentheses, combine 4r with - 11r to give - 7r.
We now have: 9 ( 8n - 7r ) + 3 ( r - n ).
Now use the distributive property on both sets of parentheses:
9 ( 8n - 7r ) = 9 x 8n - 9 x 7r = 72n - 63r 3 ( r - n ) = 3 x r - 3 x n = 3r - 3n
This becomes: 72n - 63r + 3r - 3n
Which is: 69n - 60r
9 ( 4 ( 2n + r ) - 11r ) + 3 ( r - n )
Work from the innermost parentheses first: Solve 4 ( 2n + r ) by using the distributive property:
4 ( 2n + r ) = 4 x 2n + 4 x r = 8n + 4r
This gives us: 9 ( 8n + 4r - 11r ) + 3 ( r - n )
Still working inside the first set of parentheses, combine 4r with - 11r to give - 7r.
We now have: 9 ( 8n - 7r ) + 3 ( r - n ).
Now use the distributive property on both sets of parentheses:
9 ( 8n - 7r ) = 9 x 8n - 9 x 7r = 72n - 63r 3 ( r - n ) = 3 x r - 3 x n = 3r - 3n
This becomes: 72n - 63r + 3r - 3n
Which is: 69n - 60r