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9[g-(3-g)+2]=-1+7[3g-(4+g)]

 Oct 8, 2014

Best Answer 

 #2
avatar+130511 
+5

9[g-(3-g)+2]=-1+7[3g-(4+g)]

Let's work through this one....since it's a little tricky....

Working within the brackets, first, we have

9[g- 3 + g + 2] = -1 + 7[3g - 4 - g ]

9[2g - 1 ] = -1 + 7[2g - 4 ]

Distribute the 9 and the 7 across the terms in the brackets

18g - 9 = -1 + 14g - 28      simplify

18g - 9 = -29 + 14g

Add 29 to both sides and subtract 18g from both sides

20 = -4g

Divide both sides by -4

-20/4 = -5 = g

 

 Oct 8, 2014
 #1
avatar
0

g=-2.5

 Oct 8, 2014
 #2
avatar+130511 
+5
Best Answer

9[g-(3-g)+2]=-1+7[3g-(4+g)]

Let's work through this one....since it's a little tricky....

Working within the brackets, first, we have

9[g- 3 + g + 2] = -1 + 7[3g - 4 - g ]

9[2g - 1 ] = -1 + 7[2g - 4 ]

Distribute the 9 and the 7 across the terms in the brackets

18g - 9 = -1 + 14g - 28      simplify

18g - 9 = -29 + 14g

Add 29 to both sides and subtract 18g from both sides

20 = -4g

Divide both sides by -4

-20/4 = -5 = g

 

CPhill Oct 8, 2014

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