9 minus 4x divided by -3

$$\frac{9 - 4x}{-3} = \frac{9}{-3} + \frac{-4x}{-3} ={-3 + \frac{4x}{3}<8 = \frac{4x}{3} < 11 = 4x < 33 = \mathbf{x < \frac{33}{4}.}$$

To simplify this, you can do the following:

$$\frac{9 - 4x}{-3} = \frac{9}{-3} + \frac{-4x}{-3} = \mathbf{-3 + \frac{4x}{3}.}$$

-3 + 4x

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