9^x+1 +3^2x+1=36. Solve fo x
9^(x+1) + 3^(2x+1)= 36
9^x * 9 + 3*3^(2x) = 36 divide by 3
3 * 9^x + 3^(2x) = 12
3 * 9^x + (3^2)^x = 12
3 * 9^x + 9^x = 12
9^x * (3 + 1) = 12
9^x * 4 = 12 divide by 4
9^x = 3
[3^2]^x = 3^1
3^(2x) = 3^1 equate exponents
2x = 1 → x = 1/2
