9th grade Algebra

There is a quick answer to this.....but let's solve it algebraically, first

Note   2sqrt(3) =  sqrt(12)

So.....the remaining leg is

√ [ [sqrt(12)]^2 - [sqrt (3)]^2 ]    =  √ [12 - 3] = sqrt [ 9 ] =    3 units

Note that if the hypotenuse is  2√3     and   the shortest leg  is  √3......then we have a 30 -60 -90 right triangle

The the angle opposite the hypotenuse =  90°

The angle opposite the shortest leg = 30°

So.....the remaining leg is opposite the 60°   =    √3 *√3    =     3     ...just what we  found !!!!