(9x)^2/3+(2y)^2/3+z^2/3

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Guest Jun 24, 2015

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Best Answer

$\\(9x)^2/3+(2y)^2/3+z^2/3\\\\ =(9*9*x^2)/3\quad +\quad(2*2y^2)/3\quad +\quad z^2/3\\\\ =\frac{81x^2+4y^2+z^2}{3}$

Melody Jun 24, 2015

Melody · Answer 1 · 2015-06-24T05:13:55

$\\(9x)^2/3+(2y)^2/3+z^2/3\\\\ =(9*9*x^2)/3\quad +\quad(2*2y^2)/3\quad +\quad z^2/3\\\\ =\frac{81x^2+4y^2+z^2}{3}$

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