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 a^(-1)/b^2 *(a^(-1)/(2b^2 ))^(-2)

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$${\frac{{{\mathtt{a}}}^{\left(-{\mathtt{1}}\right)}}{{{\mathtt{b}}}^{{\mathtt{2}}}}}{\mathtt{\,\times\,}}{\left({\frac{{{\mathtt{a}}}^{\left(-{\mathtt{1}}\right)}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{2}}}\right)}}\right)}^{\left(-{\mathtt{2}}\right)}$$

 May 4, 2015

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 #1
avatar+130516 
+8
a^(-1)/b^2 *(a^(-1)/(2b^2 ))^(-2) =

1 / [ ab^2] * [2b^2 / a^(-1)] ^2  =

1 /  [ ab^2] * [ 2ab*2]^2  =

1/ [ ab^2] * [ 4 a^2 b^4 ] =

4ab^2

 

  

 May 4, 2015

1+0 Answers

 #1
avatar+130516 
+8
Best Answer
a^(-1)/b^2 *(a^(-1)/(2b^2 ))^(-2) =

1 / [ ab^2] * [2b^2 / a^(-1)] ^2  =

1 /  [ ab^2] * [ 2ab*2]^2  =

1/ [ ab^2] * [ 4 a^2 b^4 ] =

4ab^2

 

  

CPhill May 4, 2015

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