A 10.0 Ω resistor is in parallel with a 30.0 Ω resistor and supplied by a 45.0 V battery. What is the total current drawn from the battery?
338 A
0.003 A
6.00 A
1.10 A
Have you seen this?
the resultant resistance of two resistors in parallel = (r1 x r2) /(r1+r2) = 300/40 = 7.5 ohms
V=IR or V/R = I 45 v /7.5 ohm = 6.00 A
hmm , no i have not yet. that makes sense! I was quite confused on this one. thank you!
You could still do it this way:
1 / (1/r1 + 1/r2) = 1 /( r2/(r2 *r1) + r1/(r2*r1) ) = R2 * R1 /( R2+R1) See how it works out? ONLY with TWO resistors in parallel though !