+0  
 
0
773
1
avatar

A 10-H inductor, a 40-uF capacitor, and a voltage supply whose voltage is given by 60sin50t are connected in series in an electric circuit. Find the current as a function of the time if the initial charge on the capacitor is zero and the initial current is zero.

 Oct 22, 2014

Best Answer 

 #1
avatar+33616 
+5

I'll start you off:

 

The relationships between current (i) and voltage (v) for capacitor and inductor are:

i = C*dv/dt     for capacitor

v = L*di/dt     for inductor

 

If they are connected in series with an ac source (V*sin(ω*t)) the following circuit equation can be written:

 

L*di/dt + v = V*sin(ω*t)  where v is the voltage across the capacitor.

 

Differentiate this with respect to time and use the capacitor equation above to get:

L*d2i/dt2 + i/C = ω*V*cos(ω*t)

 

Solve this 2nd-order differential equation for i as a function of t, making use of your initial conditions.

.

 Oct 23, 2014
 #1
avatar+33616 
+5
Best Answer

I'll start you off:

 

The relationships between current (i) and voltage (v) for capacitor and inductor are:

i = C*dv/dt     for capacitor

v = L*di/dt     for inductor

 

If they are connected in series with an ac source (V*sin(ω*t)) the following circuit equation can be written:

 

L*di/dt + v = V*sin(ω*t)  where v is the voltage across the capacitor.

 

Differentiate this with respect to time and use the capacitor equation above to get:

L*d2i/dt2 + i/C = ω*V*cos(ω*t)

 

Solve this 2nd-order differential equation for i as a function of t, making use of your initial conditions.

.

Alan Oct 23, 2014

5 Online Users

avatar
avatar