A 14,700 N car traveling at 52.5 km/h rounds a curve of radius 1.60 ✕ 102 m.

(a) What is the centripetal acceleration of the car?

m/s2

(b) What is the centripetal force?

N

(c) What is the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely?

Guest Feb 18, 2021

#1**+1 **

F_{c }= mv^{2} / r

14700 kg-m/s^{2} / 9.81 m/s^{2} = 1498.47 kg mass of car

52.5 km/hr = 14.583 m/s

F_{c}_{ }= 1498.47 * (14.583)^{2} / (160) = 1991.78 N

u_{s }= v^{2} /( rg) = 14.583^{2 }/ (160 * 9.81) = .135 (coefficient of static friction)

ElectricPavlov Feb 18, 2021