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A 14,700 N car traveling at 52.5 km/h rounds a curve of radius 1.60 ✕ 102 m.

(a) What is the centripetal acceleration of the car?
m/s2
(b) What is the centripetal force?
N
(c) What is the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely?

 Feb 18, 2021
 #1
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Fc =  mv2 / r

14700 kg-m/s2    / 9.81 m/s2 = 1498.47 kg    mass of car

52.5 km/hr = 14.583 m/s

 

     Fc  = 1498.47 * (14.583)2 / (160)   = 1991.78 N

 

us = v2 /( rg)   = 14.5832 / (160 * 9.81) = .135      (coefficient of static friction)

 Feb 18, 2021

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