a/3b-b/2a-(3a-2b)/4a-a/12b+2 how do I solve it? Thanks for any help :)

You can simplify it as follows:

1. Collect the terms with b in the denominator together:

$$\frac{a}{3b}-\frac{a}{12b}\rightarrow \frac{4a}{12b}-\frac{a}{12b}\rightarrow \frac{3a}{12b}\rightarrow \frac{a}{4b}$$

2. Collect the tems with a in the denominator together:

$$\frac{-b}{2a}-\frac{3a-2b}{4a}\rightarrow \frac{-2b}{4a}-\frac{3a-2b}{4a}\rightarrow -\frac{3}{4}$$

3. Put it all together:

$$\frac{a}{4b}-\frac{3}{4}+2\rightarrow \frac{a}{4b}+1\frac{1}{4}\rightarrow \frac{a+5b}{4b}$$

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I have exam in math tomorrow, so i dont need tha answer, but how to do it :S