A 6.5 pole is to be supported by a wire extending from the top of the pole to the ground,making an angle of 22degrees to the vertical. How long will the wire need to be?
+33652 cos angle = adjacent (height of pole)/hypotenuse (length of wire, L) so
cos(22°) = 6.5/L or L = 6.5/cos(22°)
$${\mathtt{L}} = {\frac{{\mathtt{6.5}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{22}}^\circ\right)}}} \Rightarrow {\mathtt{L}} = {\mathtt{7.010\: \!475\: \!827\: \!402\: \!684\: \!9}}$$
L ≈ 7 m
+33652 cos angle = adjacent (height of pole)/hypotenuse (length of wire, L) so
cos(22°) = 6.5/L or L = 6.5/cos(22°)
$${\mathtt{L}} = {\frac{{\mathtt{6.5}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{22}}^\circ\right)}}} \Rightarrow {\mathtt{L}} = {\mathtt{7.010\: \!475\: \!827\: \!402\: \!684\: \!9}}$$
L ≈ 7 m
