+1995 A 70.50 kg man rides a Ferris wheel with a radius of 10.3 m at a velocity of 3.00 m/s .
What is the centripetal force that he experiences, expressed with the correct number of significant figures?
The formula for determining centripetal force, in newtons, is F=mv^2/r .
62.0 N
61.6 N
61.60 N
6.2×10^1 N
i think its C
What is the product of 3.15 m and 2.006 m with the correct number of significant figures?
6 m2
6.3 m2
6.32 m2
6.319 m2
i think its A ? 6?
Please exaplin why so I can take notes. Thank you
+129852 In multiplication...the number of sig figs in the final calculated value will be the same as that of the quantity with the fewest number of sig figs used in the calculation.
70.50 = 4 sig figs
10.3 = 3 sig figs
3.00 = 3 sig figs
F = mv^2 / r = [70.50 kg ] * [3.00 m/s]^2 / [10.3m] = 61.6 N
3.15 = 3 sig figs
2.006 = 4 sig figs
3.15 * 2.006 = 6.3189 = 6.32 m^2
