+0

# A 70.50 kg man rides a Ferris wheel with a radius of 10.3 m at a velocity of 3.00 m/s .

+1
432
2

A 70.50 kg man rides a Ferris wheel with a radius of 10.3 m at a velocity of 3.00 m/s .

What is the centripetal force that he experiences, expressed with the correct number of significant figures?

The formula for determining centripetal force, in newtons, is F=mv^2/r .

62.0 N

61.6 N

61.60 N

6.2×10^1 N

i think its C

What is the product of 3.15 m and 2.006 m with the correct number of significant figures?

6 m2

6.3 m2

6.32 m2

6.319 m2

i think its A ? 6?

Please exaplin why so I can take notes. Thank you

Aug 29, 2019
edited by jjennylove  Aug 29, 2019
edited by jjennylove  Aug 29, 2019
edited by jjennylove  Aug 29, 2019

#1
+2

In multiplication...the number of sig figs in the final calculated value will be the same as that of the quantity with the fewest number of sig figs used in the calculation.

70.50   = 4 sig figs

10.3   =  3 sig figs

3.00  =  3 sig figs

F  =  mv^2 / r     =    [70.50 kg ] * [3.00 m/s]^2  / [10.3m]   =  61.6  N

3.15  =  3 sig figs

2.006  = 4 sig figs

3.15  * 2.006  = 6.3189  =  6.32 m^2   Aug 29, 2019
#2
+2

BTW...I'm not an expert on sig figs....but.....here's a site that might help :   