a+b=10 b+c=20 a+c=24 So a+b+c = ?
(a+b)+(b+c)+(a+c)=2(a+b+c)=10+20+24=54
a+b+c=54/2=27
Difference between c and a -> 20-10=10
a-> (24-10)÷2=7
c-> 10+7=17
b-> 10-7=3
a+b+c-> 7+3+17=27