(a+b)(a-b)
this would solve out to $${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{ab}}{\mathtt{\,\small\textbf+\,}}{\mathtt{ab}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}$$
so... the $${\mathtt{ab}}$$(s) will cancel out and you will end with
$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}$$ (but it'd be 2b not 2 + b)
(a+b)(a-b)
this would solve out to $${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{ab}}{\mathtt{\,\small\textbf+\,}}{\mathtt{ab}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}$$
so... the $${\mathtt{ab}}$$(s) will cancel out and you will end with
$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}$$ (but it'd be 2b not 2 + b)