A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?
A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?
3/22 * 8/22
$$\left({\frac{{\mathtt{3}}}{{\mathtt{22}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{22}}}}\right) = {\frac{{\mathtt{6}}}{{\mathtt{121}}}} = {\mathtt{0.049\: \!586\: \!776\: \!859\: \!504\: \!1}}$$
A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?
3/22 * 8/22
$$\left({\frac{{\mathtt{3}}}{{\mathtt{22}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{22}}}}\right) = {\frac{{\mathtt{6}}}{{\mathtt{121}}}} = {\mathtt{0.049\: \!586\: \!776\: \!859\: \!504\: \!1}}$$